Julie has 5 cherry lollipops,1 lime lollipops, and 2 grape lollipops in a bag. She is going to select one lollipop, replace the lollipop in the bag, and then select a second one. What is the probability that Julie will select a cherry lollipop and then a lollipop other than grape?a.)6/8b.)11/16c.)15/32d.)10/64

Answer: [tex]\dfrac{15}{32}[/tex] Step-by-step explanation:Given : The number of cherry lollipop = 5The total number of lollipop = 8the number of lollipops other than grape =6The probability of selecting a cherry lollipop is given by :_[tex]\text{P(Cherry)}=\dfrac{5}{8}[/tex]The probability of selecting a lollipop other than grape is given by :_[tex]\text{P(Other than grape)}=\dfrac{6}{8}[/tex]Since, there is replacement , then the events are independent of each other.Now, the probability that Julie will select a cherry lollipop and then a lollipop other than grape is given by :-[tex]\text{P(Cherry and other than grape)}=\dfrac{5}{8}\times\dfrac{6}{8}=\dfrac{15}{32}[/tex]Hence, the required probability =[tex]\dfrac{15}{32}[/tex]