You want to estimate the proportion of students at OSU who have ever used an online dating app. You select a random sample of 140 OSU students and find that 43% have used an online dating app. If you want to construct a 99% confidence interval, what will the margin of error be? Try not to do a lot of rounding along the way until you get to the end of your calculations?

Answer: The margin of error for the proportion of students at OSU who have ever used an online dating app in 99% confidence level is 10.8%Step-by-step explanation:margin of error (ME) around the mean can be found using the formulaME=[tex]z*\sqrt{\frac{p*(1-p)}{N} }[/tex] where z is the corresponding statistic in the given confidence level (2.58)p  the proportion of students at OSU who have ever used an online dating app in the random sample. (0.43)N is the sample size (140)Putting the numbers in the formula we getME=[tex]2.58*\sqrt{\frac{0.43*0.57}{140} }[/tex] ≈ 0,10795 ≈ 10.8%Then the confidence interval for the proportion of students at OSU who have ever used an online dating app in 99% confidence level would be 43%±10.8%